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Uniqueness related to Higher Order Difference Operators of Entire Functions

Journal of the Korean Society of Mathematical Education Series B: The Pure and Applied Mathematics / Journal of the Korean Society of Mathematical Education Series B: The Pure and Applied Mathematics, (P)1226-0657; (E)2287-6081
2023, v.30 no.1, pp.43-65
https://doi.org/https://doi.org/10.7468/jksmeb.2023.30.1.43
Xinmei Liu
Junfan Chen

Abstract

In this paper, by using the difference analogue of Nevanlinna's theory, the authors study the shared-value problem concerning two higher order difference operators of a transcendental entire function with finite order. The following conclusion is proved: Let f(z) be a finite order transcendental entire function such that &#x03BB;(f - a(z)) < &#x03C1;(f), where a(z)(&#x2208; S(f)) is an entire function and satisfies &#x03C1;(a(z)) < 1, and let &#x1D702;(&#x2208; &#x2102;) be a constant such that &#x2206;<sub>&#x1D702;</sub><sup>n+1</sup> f(z) &#x2262; 0. If &#x2206;<sub>&#x1D702;</sub><sup>n+1</sup> f(z) and &#x2206;<sub>&#x1D702;</sub><sup>n</sup> f(z) share &#x2206;<sub>&#x1D702;</sub><sup>n</sup> a(z) CM, where &#x2206;<sub>&#x1D702;</sub><sup>n</sup> a(z) &#x2208; S &#x2206;<sub>&#x1D702;</sub><sup>n+1</sup> f(z), then f(z) has a specific expression f(z) = a(z) + Be<sup>Az</sup>, where A and B are two non-zero constants and a(z) reduces to a constant.

keywords
transcendental entire function, sharing value, higher order difference operator, uniqueness

Journal of the Korean Society of Mathematical Education Series B: The Pure and Applied Mathematics